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Previous set of notes: 246A Notes 5. Next set of notes: Notes 2.
— 1. Jensen’s formula —
Suppose is a non-zero rational function
, then by the fundamental theorem of algebra one can write
Exercise 1 Letbe a complex polynomial of degree
.
- (i) (Gauss-Lucas theorem) Show that the complex roots of
are contained in the closed convex hull of the complex roots of
.
- (ii) (Laguerre separation theorem) If all the complex roots of
are contained in a disk
, and
, then all the complex roots of
are also contained in
. (Hint: apply a suitable Möbius transformation to move
to infinity, and then apply part (i) to a polynomial that emerges after applying this transformation.)
There are a number of useful ways to extend these formulae to more general meromorphic functions than rational functions. Firstly there is a very handy “local” variant of (1) known as Jensen’s formula:
Theorem 2 (Jensen’s formula) Letbe a meromorphic function on an open neighbourhood of a disk
, with all removable singularities removed. Then, if
is neither a zero nor a pole of
, we have
where
and
range over the zeroes and poles of
respectively (counting multiplicity) in the disk
.
One can view (3) as a truncated (or localised) variant of (1). Note also that the summands are always non-positive.
Proof: By perturbing slightly if necessary, we may assume that none of the zeroes or poles of
(which form a discrete set) lie on the boundary circle
. By translating and rescaling, we may then normalise
and
, thus our task is now to show that
by the useful device of Blaschke products. Suppose for instance that
has a zero
inside the disk
. Observe that the function
on the unit circle
, equals
at the origin, has a simple zero at
, but has no other zeroes or poles inside the disk. Thus Jensen’s formula (4) already holds if
is replaced by
. To prove (4) for
, it thus suffices to prove it for
, which effectively deletes a zero
inside the disk
from
(and replaces it instead with its inversion
). Similarly we may remove all the poles inside the disk. As a meromorphic function only has finitely many poles and zeroes inside a compact set, we may thus reduce to the case when
has no poles or zeroes on or inside the disk
, at which point our goal is simply to show that
An important special case of Jensen’s formula arises when is holomorphic in a neighborhood of
, in which case there are no contributions from poles and one simply has
are non-negative; it can be viewed as a more precise assertion of the subharmonicity of
(see Exercises 60(ix) and 61 of 246A Notes 5). Here are some quick applications of this formula:
Exercise 3 Use (6) to give another proof of Liouville’s theorem: a bounded holomorphic functionon the entire complex plane is necessarily constant.
Exercise 4 Use Jensen’s formula to prove the fundamental theorem of algebra: a complex polynomialof degree
has exactly
complex zeroes (counting multiplicity), and can thus be factored as
for some complex numbers
with
. (Note that the fundamental theorem was invoked previously in this section, but only for motivational purposes, so the proof here is non-circular.)
Exercise 5 (Shifted Jensen’s formula) Letbe a meromorphic function on an open neighbourhood of a disk
, with all removable singularities removed. Show that
for all
in the open disk
that are not zeroes or poles of
, where
and
. (The function
appearing in the integrand is sometimes known as the Poisson kernel, particularly if one normalises so that
and
.)
Exercise 6 (Bounded type)
- (i) If
is a holomorphic function on
that is not identically zero, show that
.
- (ii) If
is a meromorphic function on
that is the ratio of two bounded holomorphic functions that are not identically zero, show that
. (Functions
of this form are said to be of bounded type and lie in the Nevanlinna class for the unit disk
.)
Exercise 7 (Smoothed out Jensen formula) Letbe a meromorphic function on an open set
, and let
be a smooth compactly supported function. Show that
where
range over the zeroes and poles of
(respectively) in the support of
. Informally argue why this identity is consistent with Jensen’s formula. (Note: as many of the functions involved here are not holomorphic, complex analysis tools are of limited use. Try using real variable tools such as Stokes theorem, Greens theorem, or integration by parts.)
When applied to entire functions , Jensen’s formula relates the order of growth of
near infinity with the density of zeroes of
. Here is a typical result:
Proposition 8 Letbe an entire function, not identically zero, that obeys a growth bound
for some
and all
. Then there exists a constant
such that
has at most
zeroes (counting multiplicity) for any
.
Entire functions that obey a growth bound of the form for every
and
(where
depends on
) are said to be of order at most
. The above theorem shows that for such functions that are not identically zero, the number of zeroes in a disk of radius
does not grow much faster than
. This is often a useful preliminary upper bound on the zeroes of entire functions, as the order of an entire function tends to be relatively easy to compute in practice.
Proof: First suppose that is non-zero. From (6) applied with
and
one has
Just as (3) and (7) give truncated variants of (1), we can create truncated versions of (2). The following crude truncation is adequate for many applications:
Theorem 9 (Truncated formula for log-derivative) Letbe a holomorphic function on an open neighbourhood of a disk
that is not identically zero on this disk. Suppose that one has a bound of the form
for some
and all
on the circle
. Let
be constants. Then one has the approximate formula
for all
in the disk
other than zeroes of
. Furthermore, the number of zeroes
in the above sum is
.
Proof: To abbreviate notation, we allow all implied constants in this proof to depend on .
We mimic the proof of Jensen’s formula. Firstly, we may translate and rescale so that and
, so we have
when
, and our main task is to show that
. Note that if
then
vanishes on the unit circle and hence (by the maximum principle) vanishes identically on the disk, a contradiction, so we may assume
. From hypothesis we then have
Suppose has a zero
with
. If we factor
, where
is the Blaschke product (5), then
Similarly, given a zero with
, we have
, so using Blaschke products to remove all of these zeroes also only affects the left-hand side of (8) by
(since the number of zeroes here is
), with
also modified by at most
. Thus we may assume in fact that
has no zeroes whatsoever within the unit disk. We may then also normalise
, then
for all
. By Jensen’s formula again, we have
Exercise 10
- (i) (Borel-Carathéodory theorem) If
is analytic on an open neighborhood of a disk
and
, show that
(Hint: one can normalise
,
,
, and
. Now
maps the unit disk to the half-plane
. Use a Möbius transformation to map the half-plane to the unit disk and then use the Schwarz lemma.)
- (ii) Use (i) to give an alternate way to conclude the proof of Theorem 9.
A variant of the above argument allows one to make precise the heuristic that holomorphic functions locally look like polynomials:
Exercise 11 (Local Weierstrass factorisation) Let the notation and hypotheses be as in Theorem 9. Then show thatfor all
in the disk
, where
is a polynomial whose zeroes are precisely the zeroes of
in
(counting multiplicity) and
is a holomorphic function on
of magnitude
and first derivative
on this disk. Furthermore, show that the degree of
is
.
Exercise 12 (Preliminary Beurling factorisation) Letdenote the space of bounded analytic functions
on the unit disk; this is a normed vector space with norm
- (i) If
is not identically zero, and
denote the zeroes of
in
counting multiplicity, show that
and
- (ii) Let the notation be as in (i). If we define the Blaschke product
where
is the order of vanishing of
at zero, show that this product converges absolutely to a holomorphic function on
, and that
for all
. (It may be easier to work with finite Blaschke products first to obtain this bound.)
- (iii) Continuing the notation from (i), establish a factorisation
for some holomorphic function
with
for all
.
- (iv) (Theorem of F. and M. Riesz, special case) If
extends continuously to the boundary
, show that the set
has zero measure.
Remark 13 The factorisation (iii) can be refined further, withbeing the Poisson integral of some finite measure on the unit circle. Using the Lebesgue decomposition of this finite measure into absolutely continuous parts one ends up factorising
functions into “outer functions” and “inner functions”, giving the Beurling factorisation of
. There are also extensions to larger spaces
than
(which are to
as
is to
), known as Hardy spaces. We will not discuss this topic further here, but see for instance this text of Garnett for a treatment.
Exercise 14 (Littlewood’s lemma) Letbe holomorphic on an open neighbourhood of a rectangle
for some
and
, with
non-vanishing on the boundary of the rectangle. Show that
where
ranges over the zeroes of
inside
(counting multiplicity) and one uses a branch of
which is continuous on the upper, lower, and right edges of
. (This lemma is a popular tool to explore the zeroes of Dirichlet series such as the Riemann zeta function.)
Just a short announcement that next quarter I will be continuing the recently concluded 246A complex analysis class as 246B. Topics I plan to cover:
- Schwartz-Christoffel transformations and the uniformisation theorem (using the remainder of the 246A notes);
- Jensen’s formula and factorisation theorems (particularly Weierstrass and Hadamard); the Gamma function;
- Connections with the Fourier transform on the real line;
- Elliptic functions and their relatives;
- (if time permits) the Riemann zeta function and the prime number theorem.
Notes for the later material will appear on this blog in due course.
I’ve just uploaded to the arXiv my paper “Sendov’s conjecture for sufficiently high degree polynomials“. This paper is a contribution to an old conjecture of Sendov on the zeroes of polynomials:
Conjecture 1 (Sendov’s conjecture) Letbe a polynomial of degree
that has all zeroes in the closed unit disk
. If
is one of these zeroes, then
has at least one zero in
.
It is common in the literature on this problem to normalise to be monic, and to rotate the zero
to be an element
of the unit interval
. As it turns out, the location of
on this unit interval
ends up playing an important role in the arguments.
Many cases of this conjecture are already known, for instance
- When
(Brown-Xiang 1999);
- When
(Gauss-Lucas theorem);
- When
(Bojanov 2011);
- When
for a fixed
, and
is sufficiently large depending on
(Dégot 2014);
- When
for a sufficiently large absolute constant
(Chalebgwa 2020);
- When
(Rubinstein 1968; Goodman-Rahman-Ratti 1969; Joyal 1969);
- When
, where
is sufficiently small depending on
(Miller 1993; Vajaitu-Zaharescu 1993);
- When
(Chijiwa 2011);
- When
(Kasmalkar 2014).
In particular, in high degrees the only cases left uncovered by prior results are when is close (but not too close) to
, or when
is close (but not too close) to
; see Figure 1 of my paper.
Our main result covers the high degree case uniformly for all values of :
Theorem 2 There exists an absolute constantsuch that Sendov’s conjecture holds for all
.
In principle, this reduces the verification of Sendov’s conjecture to a finite time computation, although our arguments use compactness methods and thus do not easily provide an explicit value of . I believe that the compactness arguments can be replaced with quantitative substitutes that provide an explicit
, but the value of
produced is likely to be extremely large (certainly much larger than
).
Because of the previous results (particularly those of Chalebgwa and Chijiwa), we will only need to establish the following two subcases of the above theorem:
Theorem 3 (Sendov’s conjecture near the origin) Under the additional hypothesis, Sendov’s conjecture holds for sufficiently large
.
Theorem 4 (Sendov’s conjecture near the unit circle) Under the additional hypothesisfor a fixed
, Sendov’s conjecture holds for sufficiently large
.
We approach these theorems using the “compactness and contradiction” strategy, assuming that there is a sequence of counterexamples whose degrees going to infinity, using various compactness theorems to extract various asymptotic objects in the limit
, and somehow using these objects to derive a contradiction. There are many ways to effect such a strategy; we will use a formalism that I call “cheap nonstandard analysis” and which is common in the PDE literature, in which one repeatedly passes to subsequences as necessary whenever one invokes a compactness theorem to create a limit object. However, the particular choice of asymptotic formalism one selects is not of essential importance for the arguments.
I also found it useful to use the language of probability theory. Given a putative counterexample to Sendov’s conjecture, let
be a zero of
(chosen uniformly at random among the
zeroes of
, counting multiplicity), and let
similarly be a uniformly random zero of
. We introduce the logarithmic potentials
Theorem 5
- (i) If
, then
almost surely lie in the semicircle
and have the same distribution.
- (ii) If
, then
is uniformly distributed on the circle
, and
is almost surely zero.
In case (i) (and strengthening the hypothesis to
to control some technical contributions of “outlier” zeroes of
), we can use this information about
and (4) to ensure that the normalised logarithmic derivative
has a non-negative winding number in a certain small (but not too small) circle around the origin, which by the argument principle is inconsistent with the hypothesis that
has a zero at
and that
has no zeroes near
. This is how we establish Theorem 3.
Case (ii) turns out to be more delicate. This is because there are a number of “near-counterexamples” to Sendov’s conjecture that are compatible with the hypotheses and conclusion of case (ii). The simplest such example is , where the zeroes
of
are uniformly distributed amongst the
roots of unity (including at
), and the zeroes of
are all located at the origin. In my paper I also discuss a variant of this construction, in which
has zeroes mostly near the origin, but also acquires a bounded number of zeroes at various locations
inside the unit disk. Specifically, we take
Laura Cladek and I have just uploaded to the arXiv our paper “Additive energy of regular measures in one and higher dimensions, and the fractal uncertainty principle“. This paper concerns a continuous version of the notion of additive energy. Given a finite measure on
and a scale
, define the energy
at scale
to be the quantity
is the product measure on
formed from four copies of the measure
on
. We will be interested in Cantor-type measures
, supported on a compact set
and obeying the Ahlfors-David regularity condition
Note that once one fixes , the variable
in (1) is constrained to a ball of radius
, hence we obtain the trivial upper bound
contains a lot of “additive structure”, one can expect this bound to be basically sharp; for instance, if
is an integer,
is a
-dimensional unit disk, and
is Lebesgue measure on this disk, one can verify that
(where we allow implied constants to depend on
. However we show that if the dimension is non-integer, then one obtains a gain:
Theorem 1 Ifis not an integer, and
are as above, then
for some
depending only on
.
Informally, this asserts that Ahlfors-David regular fractal sets of non-integer dimension cannot behave as if they are approximately closed under addition. In fact the gain we obtain is quasipolynomial in the regularity constant
:
Our higher-dimensional argument shares many features in common with that of Dyatlov and Zahl, notably a reliance on the modern tools of additive combinatorics (and specifically the Bogulybov-Ruzsa lemma of Sanders). However, in one dimension we were also able to find a completely elementary argument, avoiding any particularly advanced additive combinatorics and instead primarily exploiting the order-theoretic properties of the real line, that gave a superior value of , namely
One of the main reasons for obtaining such improved energy bounds is that they imply a fractal uncertainty principle in some regimes. We focus attention on the model case of obtaining such an uncertainty principle for the semiclassical Fourier transform
It remains a largely open problem to establish a fractal uncertainty principle in higher dimensions. Our results allow one to establish such a principle when the dimension is close to
, and
is assumed to be odd (to make
a non-integer). There is also work of Han and Schlag that obtains such a principle when one of the copies of
is assumed to have a product structure. We hope to obtain further higher-dimensional fractal uncertainty principles in subsequent work.
We now sketch how our main theorem is proved. In both one dimension and higher dimensions, the main point is to get a preliminary improvement , provided
is sufficiently small depending on
; one can then iterate this bound by a fairly standard “induction on scales” argument (which roughly speaking can be used to show that energies
behave somewhat multiplicatively in the scale parameter
) to propagate the bound to a power gain at smaller scales. We found that a particularly clean way to run the induction on scales was via use of the Gowers uniformity norm
, and particularly via a clean Fubini-type inequality
It remains to obtain the preliminary improvement. In one dimension this is done by identifying some “left edges” of the set that supports
: intervals
that intersect
, but such that a large interval
just to the left of this interval is disjoint from
. Here
is a large constant and
is a scale parameter. It is not difficult to show (using in particular the Archimedean nature of the real line) that if one has the Ahlfors-David regularity condition for some
then left edges exist in abundance at every scale; for instance most points of
would be expected to lie in quite a few of these left edges (much as most elements of, say, the ternary Cantor set
would be expected to contain a lot of
s in their base
expansion). In particular, most pairs
would be expected to lie in a pair
of left edges of equal length. The key point is then that if
lies in such a pair with
, then there are relatively few pairs
at distance
from
for which one has the relation
, because
will both tend to be to the right of
respectively. This causes a decrement in the energy at scale
, and by carefully combining all these energy decrements one can eventually cobble together the energy bound (3).
We were not able to make this argument work in higher dimension (though perhaps the cases and
might not be completely out of reach from these methods). Instead we return to additive combinatorics methods. If the claim (3) failed, then by applying the Balog-Szemeredi-Gowers theorem we can show that the set
has high correlation with an approximate group
, and hence (by the aforementioned Bogulybov-Ruzsa type theorem of Sanders, which is the main source of the quasipolynomial bounds in our final exponent)
will exhibit an approximate “symmetry” along some non-trivial arithmetic progression of some spacing length
and some diameter
. The
-neighbourhood
of
will then resemble the union of parallel “cylinders” of dimensions
. If we focus on a typical
-ball of
, the set now resembles a Cartesian product of an interval of length
with a subset of a
-dimensional hyperplane, which behaves approximately like an Ahlfors-David regular set of dimension
(this already lets us conclude a contradiction if
). Note that if the original dimension
was non-integer then this new dimension
will also be non-integer. It is then possible to contradict the failure of (3) by appealing to a suitable induction hypothesis at one lower dimension.
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